计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)
人气:430 ℃ 时间:2020-02-04 00:58:17
解答
(1/2+1/3+1/4+…+1/2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2006)(1/2+1/3+…1/2005)=(1+1/2+1/3+1/4+…+1/2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2006)(1/2+1/3+…1...
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