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y=e^[tan(1/x)] 求导数
人气:106 ℃ 时间:2019-11-22 18:51:56
解答
y'=e^[tan(1/x)]*[tan(1/x)]'
=e^[tan(1/x)]*[sec(1/x)]^2*(1/x)'
=-{e^[tan(1/x)]*[sec(1/x)]^2}/x^2
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