证明：在AP上取点D,使CD＝PC,连接BD∵等边△ABC∴AC＝BC,∠ABC＝∠ACB＝60∴∠ACD+∠BCD＝60∵∠APC、∠ABC所对应圆弧都为劣弧AC∴∠APC＝∠ABC＝60∵CD＝PC∴等边△PCD∴∠PCD＝60,PD＝PC∴∠BCP+∠BCD＝60∴∠BCP...