等差数列a1+a2+a5+a8+a9=25 求S9
人气:386 ℃ 时间:2020-04-20 00:36:54
解答
a1+a2+a5+a8+a9=25
5*a5=25
a5=5
S9=a1+a2+a3+...+a9
=9*a5
=9*5
=45
推荐
- 等差数列a1+a2+a5+a8+a9=30,a5=?
- 已知{an}为等差数列,若a1+a5+a9=π,则cos(a2+a8)的值为( ) A.−12 B.−32 C.12 D.32
- 在等差数列a(n)中,若a2+a4+a5+a6+a8=450,求a1+a9
- 等差数列an中,a1+a4+a7=39,a2+a5+a8=33,a3+a6+a9=?
- 已知等差数列{an}中,a1+a4+a7=39,a2+a5+a8=33,求a3+a6+a9的值
- 描述自己最理想的生活方式?
- 英语翻译:It was built in the early 12th century by King Suryavarman II as his state temple.
- 帮我写三个将来时态,三个现在时态.
猜你喜欢