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函数f(x)=-3sin(2x-π/6)的单调递减区间为
人气:498 ℃ 时间:2020-03-29 14:25:26
解答
求函数f(x)=-3sin(2x-π/6)的单调递减区间即求y=3sin(2x-π/6)的单调增区间∴ 2kπ-π/2≤2x-π/6≤2kπ+π/2,k∈Z∴ 2kπ-π/3≤2x≤2kπ+2π/3,k∈Z∴ kπ-π/6≤x≤kπ+π/3,k∈Z∴ 函数f(x)=-3sin(2x-π/6)的单...
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