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(tan10º-√3)sin40º 怎么求值?
人气:262 ℃ 时间:2020-05-18 18:57:21
解答
(tan10º-√3)sin40º
=(sin10°/cos10°-√3)sin40º
=(sin10°-√3cos10°)sin40º/cos10°
=-2cos(10°+30°)sin40º/cos10°
=-2cos40°sin40°/cos10°
=-sin80°/cos10°
=-cos10°/cos10°
=-1
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