点P(1,2,3)与平面π:X-2Y+2Z+1=0之间的距离
人气:170 ℃ 时间:2020-05-26 02:56:17
解答
由距离公式得所求距离为
d=|1-2×2+2×3+1|/√[1^2+(-2)^2+(2)^2]
=4/3
注:**点(X0,Y0,Z0)到面的距离公式为
d=|AX0+BY0+CZ0+D|√(A^2+B^2+C^2)**
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