> 数学 >
(4/9)^(-sinπ/6)-2lg(cos0)+(0.125)^(log2 (1/3))=
人气:433 ℃ 时间:2020-06-23 18:59:03
解答
(4/9)^(-sinπ/6)-2lg(cos0)+(0.125)^(log2 (1/8))
=(4/9)^(-1/2)-2lg1+(1/8)^(-3)
=(2/3)^(-1/2×2)-0+8³
=3/2+512
=513.5
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版