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8^(-1/3)-(1/2)^log2 6-2lg(1/4)+4lg5=
人气:113 ℃ 时间:2020-09-01 14:35:31
解答
8^(-1/3)-(1/2)^log2 6-2lg(1/4)+4lg5
=(1/8)^(1/3) -2^log2(1/6) +2lg4 +4lg5
=1/2 -1/6 +4lg2+4lg5
=1/3 +4(lg2+lg5)
=1/3 +4
=13/3
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