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已知X+Y=2,求(X²-Y²)²--8(X²+Y²)的值
人气:259 ℃ 时间:2020-06-18 08:49:30
解答
已知X+Y=2
(X+Y)²=X²+Y²+2XY=4
X²+Y²=4-2XY
(X²-Y²)²--8(X²+Y²)
=(X²+Y²)²-8(X²+Y²)-4X²Y²
=(X²+Y²)(X²+Y²-8)-4X²Y²
=(4-2XY)(4-2XY-8)-4X²Y²
=-(4-2XY)(4+2XY)-4X²Y²
=-16
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