1/ln(n+1)+1/ln(n+2)……1/ln(n+2013) >2013/n(n+2013)_数学解答

1/ln(n+1)+1/ln(n+2)……1/ln(n+2013) >2013/n(n+2013)

人气：318 ℃　时间：2020-06-13 14:56:34

解答

∵0[1/n-1/(n+1)]+[1/(n+1)-1/(n+2)]+...+[1/(n+2012)-1/(n+2013)]
=1/n-1/(n+2013)
=2013/[n*(n+2013)]