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求不定积分∫e^〔(x)^2〕dx=
人气:436 ℃ 时间:2020-03-23 14:43:26
解答
∫e^〔(x)^2〕dx
= x*e^(x^2) - ∫xde^(x^2)
=x*e^(x^2) - ∫2*(x^2)*e^(x^2)dx
=x*e^(x^2) - ∫(x^2)*e^(x^2)d(x^2)
=x*e^(x^2) -(x^4)*e^(x^2) +e^(x^2)
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