∫[1→5] (|2-x|+|sinx|) dx=∫[1→5] |2-x| dx+∫[1→5] |sinx| dx=∫[1→2] (2-x) dx+∫[2→5] (x-2) dx+∫[1→π] sinx dx-∫[π→5] sinx dx=(2x-(1/2)x²) |[1→2] + ((1/2)x²-2x) |[2→5] -cosx |[1...