2x/(x+1)+3/(x-1)=2
两边都乘以(x+1)(x-1)得,2x(x-1)+3(x+1)=2(x+1)(x-1)
∴2x²-2x+3x+3=2x²-2
x=-5
把x=5代入(x+1)(x-1)中,(x+1)(x-1)≠0,∴x=5是方程的根.