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因式分解(1)2x²-32(2)(x-1)²-9(3)a的五次方-a(4)16x²-9y²
人气:101 ℃ 时间:2019-08-17 23:53:33
解答
(1)2x²-32
=2(x²-16)
=2(x+4)(x-4)
(2)(x-1)²-9
=[(x-1)+3][(x-1)-3]
=(x+2)(x-4)
(3)a的五次方-a
=a(a的4次方-1)
=a(a²+1)(a²-1)
=a(a²+1)(a+1)(a-1)
(4)16x²-9y²
=(4x)²-(3y)²
=(4x+3y)(4x-3y)·16x的四次方-81y的四次方·(x-y)²-4(x+y)²就这两道题了,=(4x²)²-(9y²)²=(4x²+9y²)(4x²-9y²)=(4x²+9y²)(2x+3y)(2x-3y) =(x-y)²-[2(x+y)]²=(x-y+2x+2y)(x-y-2x-2y)=(3x+y)(-x-3y)=-(3x+y)(x+3y)
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