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上题就算了 x^2-(y-z)^2分之x^2-y^2除以(x-y)^2-z^2分之x^2+2xy+y^2乘以x^2-xy分之x^2+xy-xz
人气:130 ℃ 时间:2020-06-22 21:46:57
解答
原式=(x+y)(x-y)/(x+y-z)(x-y+z)÷(x+y)²/(x-y+z)(x-y-z)×x(x+y-z)/x(x-y)
=(x+y)(x-y)/(x+y-z)(x-y+z)×(x-y+z)(x-y-z)/(x+y)²×(x+y-z)/(x-y)
=(x-y)(x-y-z)/(x+y-z)(x+y)×(x+y-z)/(x-y)
=(x-y-z)/(x+y)
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