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1/1980+1/1981+1/1983+1/1984+1/1985=?
人气:177 ℃ 时间:2020-05-04 20:53:52
解答
1/1980+1/1981+1/1983+1/1984+1/1985
=1/(1983-2)+1/(1983-1)+1/1983+1/(1983+1)+1/(1983+2)
=(1*1985+1*1983)/(1983∧2-2∧2)+1/1983+(1*1984+1*1982)/(1983∧2-1∧2)
=3968/1983∧2-4+1/1983+3966/(1983∧2-1)
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