(2x+1)(4x-2)=(2x-1)^2+2
x=1/2 (-1 - 根号[6])
x=1/2 (-1 + 根号[6])
(x+1)(x-1)+2(x+3)=8
x=1 x=-3过程呢？(2x+1)(4x-2)=(2x-1)^2+2-2 + 8 x^2=3 - 4 x + 4 x^2公式法：x=1/2 (-1 - 根号[6])x=1/2 (-1 + 根号[6])(x+1)(x-1)+2(x+3)=85 + 2 x + x^2=82 x + x^2-3=0(x-1)(x+3)=0x=1x=-3