234*12.1+235*42.2-135*54.3
235*12.1+235*42.2-135*54.3
人气:396 ℃ 时间:2020-05-01 17:03:30
解答
234*12.1+235*42.2-135*54.3
=(235-1)*12.1+235*42.2-135*54.3
=235*12.1-12.1+235*42.2-135*54.3
=(235*12.1+235*42.2)-135*54.3-12.1
=235*(12.1+42.2)-135*54.3-12.1
=235*54.3-135*54.3-12.1
=(235-135)*54.3-12.1
=100**54.3-12.1
=5430-12.1
=5417.9
235*12.1+235*42.2-135*54.3
=235*(12.1+42.2)-135*54.3
=54.3*(235-135)
=5430
我是最先作答的哦,不明白欢迎追问.
推荐
- 235*12.1+235*42.2-135*54.3=?
- 235×12.1+235×42.2-135×54.3 (简便算法)
- 第一题:53.5*35.3+53.5*43.2+78.5*46.5第二题:235*12.1+235*42.2-135*54.3
- 228.230.235.231.235.232.235.234.233.229.234.235.找出中位数和众数
- 用简便方法做235+618*234/235*618-383
- 12分之11、18分之7和6分之5 4分之5、3分之4和6分...
- (1)两个平行四边形A、B重叠在一起,重叠部分的面积是A的4分之1,是B的6分之1.已知A的面积是12平方厘米.求B比A的面积多多少平方厘米.
- )设X服从N(0,1),(X1,X2,X3,X4,X5,X6)为来自总体X的简单随机样本,Y=(X1+X2+X3+)^2+(X4+X5+X6X)^2 求c,使得cy服从X^2(卡方分布)
猜你喜欢