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比较大小tan12π/5与tan(-16/3π)
人气:434 ℃ 时间:2020-06-26 08:07:18
解答
tan12π/5
=tan(12π/5-2π)
=tan(2π/5)>0
tan(-16/3π)
=tan(-16π/3+3π)
=tan(-π/3)
=-tanπ/3tan(-16/3π)
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