是增函数呀 楼主写错了吧设x1,x2是满足x1＞x2＞0的任意实数f(x1)=x1³f(x2)=x2³f(x1)-f(x2)=x1³-x2³=(x1-x2)(x1²+x1x2+x2²)显然x1-x2＞0 x1²+x1x2+x2²＞0所以(x1-x2)(x1&sup...