当然有.原函数=∫e^x (1-cos2x)/2dx=0.5[e^x- ∫e^xcos2xdx]再求e^xcos2x的原函数,用分部积分法.I=∫e^xcos2xdx=e^xcos2x+∫2e^xsin2xdx=e^xcos2x+2[e^xsin2x-∫2e^xcos2xdx]=e^xcos2x+2e^xsin2x-4I得：I=e^x(cos2x+...