1.已知f(x)=x2+2x.求f(2x+1)的解析式f(2x+1)=(2x+1)^2+2(2x+1)=4x^2+8x+32.已知f(x-1)=x²-3x+2.求f(x+1)的解析式f(x-1)=x²-3x+2令x-1=t,x=t+1代入f(t)=(t+1)^2-3(t+1)+2=t^2-tf(x+1)=(x+1)^2-(x+1)=x^2+x3...