求证：若a、b均为正数,且3a^3+6a^2b-3a^2c-6abc=0,则a=c.
人气：461 ℃ 时间：2020-03-29 09:35:41
解答
3a^3+6a^2b-3a^2c-6abc
=3a^2(a+2b)-3ac(a+2b)
=3a(a-c)(a+2b)=0
a、b均为正数
a>0
a+2b>0
so a-c=0
so a=c
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