已知函数f(x)=x^3-3ax(a>0)当a=1,求f(x)的单调区间.
人气:185 ℃ 时间:2019-09-13 20:48:25
解答
a=1
f(x)=x³-3x
f'(x)=3x²-3=0
x=±1
所以x1,f'(x)>0,增函数
-1
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