故132=
| 132−1 |
| 2 |
| 132+1 |
| 2 |
（2）规律为：（2n+1）2=（
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |
（3）（
| (2n+1)2+1 |
| 2 |
| (2n+1)2−1 |
| 2 |
=[（
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |
=（2n+1）2．
即三个数是勾股数．
| 132−1 |
| 2 |
| 132+1 |
| 2 |
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |
| (2n+1)2+1 |
| 2 |
| (2n+1)2−1 |
| 2 |
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |
| (2n+1)2−1 |
| 2 |
| (2n+1)2+1 |
| 2 |