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∫[0,1]dx∫[x,√x]siny/ydy 的二重积分
人气:475 ℃ 时间:2020-04-21 17:16:05
解答
交换积分次序:∫[0,1]dx∫[x,√x]siny/ydy=∫[0,1]dy∫[y²--->y] siny/y dx=∫[0,1] (siny/y)(y-y²)dy=∫[0,1] (siny-ysiny)dy=∫[0,1] sinydy-∫[0,1] ysinydy=-cosy+∫[0,1] yd(cosy)=-cosy+ycosy-∫[0...
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