已知圆x²+y²-4x-14y+45=0 ,求y-3/(y+2)的最值
人气:245 ℃ 时间:2020-05-24 10:40:01
解答
M(x,y)是圆C:x^2 +y^2-4x-14y+ 45=0①上的任意一点,设k=(y-3)/(x +2),则y=kx+2k+3,代入①,x^+k^x^+(4k^+6k)x+(2k+3)^-4x-14(kx+2k+3)+45=0,整理得(1+k^)x^+(4k^-8k-4)x+4k^-16k+12=0,k,x∈R,∴△/16=(k^-2k-1)^-(k...
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