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数学
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x^4-4x^3+10x^2-12x+9
分解因式,且x为有理数
人气:245 ℃ 时间:2020-04-12 06:47:03
解答
x^4-4x^3+10x^2-12x+9
=(x^4-4x^3+6x^2-4x+1)+(4x^2-8x+4)+4
=(x-1)^4+4(x-1)^2+4
=[(x-1)^2+2]^2>=4
所以
X^4-4X^3+10X^2-12X+9的最小值是4
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