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已知tanx,tany是方程x^2+6x+7=0的两个根,求证sin(x+y)=cos(x+y).
人气:276 ℃ 时间:2020-02-06 03:46:49
解答
tanx+tany=-6,tanx*tany=7
tan(x+y)=(tanx+tany)/(1-tanxtany)
=(-6)/(1-7)=1
tan(x+y)=sin(x+y)/cos(x+y)=1
sin(x+y)=cos(x+y).
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