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设siny-e^x+xy^2=0,求dy/dx
人气:498 ℃ 时间:2019-09-22 06:36:36
解答
siny-e^x+xy^2=0
cosy.y' -e^x + 2xy.y' +y^2 =0
(cosy+2xy)y' = e^x-y^2
y' = (e^x-y^2)/(cosy+2xy)
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