x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z
人气:253 ℃ 时间:2020-02-03 08:57:21
解答
x=1,
y=2,
z=3
联立任意两个,消除z,
x+2y+3z=14
2x+y+z=7
5x+y=7
再联立其他的的两个.消除z
2x+y+z=7
3x+y+2z=11
x+y=3
然后联立这两个
x+y=3
5x+y=7
解得x=1,y=2
代入任意一个方程x+2y+3z=14
z=3
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