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当a+b=3,x-y=1时,代数式a²+2ab+b²-x+y+1997的值是?
人气:289 ℃ 时间:2020-02-20 15:31:48
解答

a²+2ab+b²-x+y+1997

=(a+b)²-(x-y)+1997

=3²-1+1997

=8+1997

=2005


担心不显示平方符号,图片格式为

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