=[(3x²-1)-(x+2)+(1-2x²)]/(x²-3x+2)
=(3x²-1-x-2+1-2x²)/(x²-3x+2)
=(x²-x-2)/(x²-3x+2)
=(x-2)(x+1)/(x-2)(x-1)
=(x+1)/(x-1)