[(x+1)/(x^2-3x+2)]+[x/(2x^2-x-1)]-[(x-1)/(2x^2-3x-2)] =(x+1)/[(x-2)(x-1)]+x/[(2x+1)(x-1)]-(x-1)/[(2x+1)(x-2)]=(x+1)/[(x-2)(x-1)]+[x(x-2)-(x-1)^2]/[(2x+1)(x-1)(x-2)]=[(x+1)(2x+1)-1]/[(2x+1)(x-1)(x-2)]=...