已知想x²+y²=2,xy=½,求代数式(2x²-y-3xy)-(x²-2y+xy)的值
人气:292 ℃ 时间:2019-08-18 03:04:49
解答
x²+y²=2,xy=½,x+y=±√3x-y=±1解得(x,y)为:((√3+1)/2,(√3-1)/2) ((√3-1)/2,(√3+1)/2) (-(√3+1)/2,(1-√3)/2) ((1-√3)/2,-(√3+1)/2)四组解(2x²-y-3xy)-(x²-2y+xy)=x²+y-4xy...
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