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数学
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用换元法计算不定积分∫cos(3x+2)dx
人气:491 ℃ 时间:2020-04-15 02:49:23
解答
令t=3x+2,则dt=3dx→dx=1/3·dt
∫cos(3x+2)dx
=∫cost·1/3·dt
=1/3·∫cost dt
=1/3·sint+C
=1/3·sin(3x+2)+C则dt=3dx→dx=1/3·dt???不懂t=3x+2,则dt=d(3x+2)=3dx
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