令t=2x-π/12,则2x+π/6=2t+π/4,所以y=2sin(2x+π/6)+2sin(2x-π/12)=2sin（t+π/4）+2sint=√2sint+√2cost+2sint=（√2+2）sint+√2cost=2√（2+√2）sin（t+θ）（其中tanθ=√2-1）所以原函数的最大值为2√（2+...