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P为双曲线
x2
9
y2
16
=1
上一点,F1、F2是它的两个焦点,当∠F1PF2为钝角时,点P的纵坐标的取值范围是______.
人气:245 ℃ 时间:2020-06-29 04:16:53
解答
设P(x,y),则
∵F1(-5,0),F2(5,0),
PF1
=(-5-x,-y),
PF2
=(5-x,-y),
PF1
PF2
=(-5-x,-y)•(5-x,-y)=x2+y2-25=
25
16
y2
-9,
∵∠F1PF2为钝角,
25
16
y2
-9<0且y≠0,
∴-
12
5
<y<
12
5
且y≠0.
故答案为:-
12
5
<y<
12
5
且y≠0.
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