∫ x + [(sin√x)/√x]dx
=∫ x + [(sin√x)/√x]dx
= 1/2 x^2 + 2∫(sin√x) d√x
= 1/2 x^2 - 2cos√x + C
∫ [ x+(sin√x)] /√x dx
=∫ √x + [(sin√x)/√x]dx
= 2/3 x^(3/2) + 2∫(sin√x) d√x
= 2/3 x^(3/2) - 2cos√x + C