如图,在三角形ABC中,AB=AC,P为BC上任意一点,请用学过的知识说明：AB^2-AP^2=PB*PC
RT
人气：249 ℃ 时间：2019-08-21 08:45:21
解答
过点A作高AD垂直BC于点D在RT△ABD中AB²=AD²+BD²【勾股定理】在RT△APD中AP²=AD²+PD²【勾股定理】AB²-AP²=（AD²+BD²）-（AD²+PD²）=AD²+BD²-...
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