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,线段AB上有两点C、D,AC:BC=5:7,AD:BD=5:11,且CD=15cm,求AB的长.
人气:205 ℃ 时间:2019-08-21 16:02:37
解答
AC:BC=5:7
AC:(AC+BC)=5:(5+7)
AC:AB=5:12
AC=5AB/12
AD:BD=5:11
AD:(AD+BD)=5:(5+11)
AD:AB=5:16
AD=5AB/16
CD=AC-AD=5AB/12-5AB/16
=5AB(4-3)/48
=5AB/48=15
AB/48=3
AB=48*3=144cm
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