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当x=根号2004-1时,求(x+1)²-6的值
人气：378 ℃　时间：2020-05-20 07:05:22
解答

(x+1)²-6=x2+2x+1-6

= x2+2x-5

=(√2004-1)2+2×(√2004-1)-5

=2004-2√2004 +1 +2√2004-2-5

=2004 -6

=1998

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