3a-5b+19=0,a+8b-1=0,求【（4a+3b）2的平方】-8a-6b的值?_数学解答

3a-5b+19=0,a+8b-1=0,求【（4a+3b）2的平方】-8a-6b的值?

人气：448 ℃　时间：2019-10-10 04:03:45

解答

3a-5a=-19①
a+8b=1②
①+②得
4a+3b=-18
[(4a+3b)^2]-8a-6b
=18^2-2(4a+3b)
=18^2+36
=324+36
=360