已知3a-5b+19=0,a+8b-1=0,求(4a+3b)^2-8a-6a的值
已知3a-5b+19=0,a+8b-1=0,求(4a+3b)^2-8a-6a的值
人气:211 ℃ 时间:2019-09-22 07:19:57
解答
3a-5b+19=0,a+8b-1=0
两式相加,得4a+3b+18=0,即4a+3b=-18
(4a+3b)^2-8a-6a=(4a+3b)^2-2*(4a+3b)=(4a+3b)(4a+3b-2)=(-18)*(-20)=360
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