汶川地震,震后2小时,某武警率部队从 XX县出发去营救,13日凌晨1：15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因_数学解答

汶川地震,震后2小时,某武警率部队从 XX县出发去营救,13日凌晨1：15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13日23时15分到达汶川~
求先遣分队从理县到汶川的平均速度是多少?
我会加的!
还求从开始到理县的时间从理县到汶川的速度和时间（这是表格）
从开始到理县是30千米,从理县到汶川是60千米
是求从XX县到理县的时间从理县到汶川的速度和时间
求先遣分队从理县到汶川的平均速度是多少?
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人气：469 ℃　时间：2020-04-08 12:04:05

解答

设先遣分队从理到汶川的平均速度是X千米每时
用时22小时,但步行时间T=22-1=21小时
由题意列方程：（30/x）+[60/(x+x/9)]=21
解方程得：84/x=21
x=4千米每时
答：先遣分队从理到汶川的平均速度是4千米每时.（不好意思刚看到题目,希望对有所帮助）