先化简,再求值3x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y
先化简,再求值:3x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y,其中x,y满足(x+2)²+丨y-1丨=0
人气:414 ℃ 时间:2019-08-19 06:17:17
解答
x,y满足(x+2)²+丨y-1丨=0,则x+2=0,x=-2;y-1=0,y=13x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y=3x²y-(2xy²-2xy+3x²y+2xy)-2x²y=3x²y-2xy²-3x²y-2x²y...
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