先化简,再求值3x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y
先化简,再求值：3x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y,其中x,y满足（x+2）²+丨y-1丨＝0
人气：252 ℃ 时间：2019-08-19 06:17:17
解答
x,y满足（x+2）²+丨y-1丨＝0,则x+2=0,x=-2；y-1=0,y=13x²y-[2xy²-2(xy-3/2x²y)+2xy]-2x²y=3x²y-（2xy²-2xy+3x²y+2xy）-2x²y=3x²y-2xy²-3x²y-2x²y...
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