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因式分解1.(x-y)(2x-2y-3)-2 2.(a^2+b^2+c^2-2ab-2bc+2ac) 3.(2x^4y^2-4x^3y^2+10xy^4)
人气:263 ℃ 时间:2019-08-26 05:08:24
解答
1.原式=(x-y)[2(x-y)-3]-2
=2(x-y)(x-y)-3(x-y)-2
=(2x-2y+1)(x-y-2)
2..a^2+b^2+c^2-2ab-2bc+2ac
=(a-b+c)^2=[a-(b-c)}^2=a^2-2a*(b-c)+(b-c)^2=a^2-2ab+2ac+b^2-2bc+c^2=a^2-2a*(b-c)+(b-c)^2=(a-b+c)^2
3.2x^4y^2-4x^3y^2+10xy^4=2xy^2(x^3-2x^2+5y^2).
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