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(sin39° -sin21°)/(cos39°-cos21°)
人气:251 ℃ 时间:2020-09-19 12:06:39
解答
sin39° -sin21°
=sin(60°-21°)-sin21°
=√3/2*cos21°-1/2*sin21°-sin21°
=√3/2*cos21°-3/2 sin21°
=√3(1/2 *cos21°-√3/2 sin21°)
cos39°-cos21°
=cos(60°-21°)-cos21°
=1/2 cos21°+√3/2 sin21°-cos21°
=√3/2 sin21°-1/2 cos21°
所以原式= - √3
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