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(sin24°cos6°-sin66°sin6°)/(sin21°cos39°-cos21°sin39°)
人气:197 ℃ 时间:2020-09-24 05:59:01
解答
(sin24°cos6°-sin66°sin6°)/(sin21°cos39°-cos21°sin39°)
=(sin24°cos6°-cos24°sin6°)/(sin21°cos39°-cos21°sin39°)
=sin(24°-6°)/sin(21°-39°)
=sin18°/sin(-18°)
=-sin18°/sin18°
=-1
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